22=t^2-9t

Solution for 22=t^2-9t equation:

22=t^2-9t

We move all terms to the left:

22-(t^2-9t)=0

We get rid of parentheses

-t^2+9t+22=0

We add all the numbers together, and all the variables

-1t^2+9t+22=0

a = -1; b = 9; c = +22;
Δ = b2-4ac
Δ = 92-4·(-1)·22
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-13}{2*-1}=\frac{-22}{-2}
=+11
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+13}{2*-1}=\frac{4}{-2}
=-2
$